Question

a a A double convex lens has two surfaces of equal radii
'R and refractive index n = 1.5. find the focal
length
please I want step by step answer
do fast I will mark you as brainlist if you give me answer step by step​​​​

Answer 1

Step-by-step explanation:

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:$\longrightarrow$ The focal length, f = R .

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:$\Longrightarrow$ Given :-

:$\Longrightarrow$ Radius of curvature = R.

:$\Longrightarrow$ focal length = f.

:$\Longrightarrow$ Refractive index,  μ = 1.5

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:$\Longrightarrow$ From lens maker's formula :-

:$\Longrightarrow$ $\frac{1}{f}$ = (μ−1) $\left\lceil \frac{1}{R1 - \frac{1}{R2}} \right\rceil$

:$\Longrightarrow$ $\frac{1}{f}$ = (1.5 - 1) $\left\lceil \frac{1}{R - \frac{1}{R}} \right\rceil$

:$\Longrightarrow$ = 0.5× $\frac{2}{R}$

:$\Longrightarrow$ $\frac{1}{f}$ = $\frac{1}{R}$

:$\Longrightarrow$ f = R.

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$\bold\star\purple{\underline{That's\ all}}\star$

$\bold\star\orange{\underline{Hope\ it\ helps\ you}}\star$