Question

a/(a-b)+b/(a+b)+2ab/(a^2-b^2)​

Answer 1

(a+b)² = a²+b²-2ab

hope it helps

Answer 2

Answer:

the question is wrong it should be

a/(a-b)-b/(a+b)+2ab/(a^2-b^2)

Step-by-step explanation:

a/(a-b) - b/(a+b) + 2ab/(a^2-b^2)

a×(a+b)/(a-b)×(a+b) - b×(a-b)/(a+b)×(a-b) + 2ab/(a^2-b^2)

a(a+b) - b(a-b) /(a+b) (a-b) +2ab/(a^2-b^2)

a^2+ab-ba+b^2/(a+b)(a-b) + 2ab/(a^2-b^2)

a^2+b^2/(a+b)(a-b) + 2 ab/(a+b)(a-b)

a^2+b^2+2ab/(a+b)(a-b)

(a+b)^2/(a+b) (a-b)

a+b/a-b

Therefore a+b/a-b is the answer