: a (a - b) + b (b-c) + c (c-a)
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Answered by
0
Answer:
a(a-b)+b(b-c)+c(c-a)
=a²-ab+b²-bc+c²-ca
=a²+b²+c²-ab-bc-ca
As we know a²+b²+c²=(a+b+c)²-2ab-2bc-2ca
=(a+b+c)²-2ab-2bc-2ca-ab-bc-ca
=(a+b+c)²-3ab-3bc-3ca
Answered by
0
Answer:
Step-by-step explanation:
a(a-b) + b (b-c) +c(c-a)
2a-ab +2b-bc +2c-ca
2b+2b+2c-ab-bc-ca
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