Question

A = {a,b,c}, B = {p,q,r} then A-(A n B)=


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Answer 1

Hello, Buddy!!

ɢɪᴠᴇɴ:-

• A = {a,b,c}
• B = {p,q,r}

ᴛᴏ ꜰɪɴᴅ:-

• A-(A∩B)

ʀᴇQᴜɪʀᴇᴅ ꜱᴏʟᴜᴛɪᴏɴ:-

A∩B = {a,b,c} ∩ {p,q,r}

A∩B = {} [Empty Set]

A-(A∩B) = {a,b,c} - {}

A-(A∩B) = {a,b,c}

• {a,b,c} = A

$\boxed{\tt{@MrMonarque♡}}$

Hope It Helps You ✌️

Answer 2

Answer:

hope it helps. please mark me as BRAINLIEST

Step-by-step explanation:

From then definiation of Relation

Let R be a relation from A to B

i.e., R⊆A×B, then

Domain of {a:a∈A,(a,b)∈R for some b∈B}

Range of R={ b:b∈B,(a,b)∈R for some a∈A}.

Therefore,

(A) R,={(a,p),(b,s),(c,s)} is a relation as {a,b,c}⊆A and {p,r,s}⊆B.

(B) R

2

={(q,b),(c,s),(d,r)} is not a relation as q is not from set A.

(C) R

3

={(a,p),(a,q),(d,p),(c,r),(b,r)} is a relation as {a,d,c,b}⊆A and {p,q,r}⊆B.

(D)R

4

={(a,p),(q,a),(b,s),(s,b)} is not a relation as q and s does not belong to set A.