A={a,b,p} , B={2,3}, C={p,q,r,s} then n[ (AUC) x B ] is
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Answer:
n{(AUC)×B}= {(a,b,p,q,r,s)(2,3)}
n{(AUC)×B}= {( a,2),(b,2),(p,2),(q,2),(r,2),(s,2),(a,3),(b,3),(p,3),(q,3),(r,3),(s,3)}
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Question:-
A={a,b,p} , B={2,3}, C={p,q,r,s} then what is the value of n[(AUC) x B] ?
Required Answer:-
Given:-
- A={a,b,p}
- B={2,3}
- C={p,q,r,s}
To Find:-
- n[(AUC) x B]
Solution:-
Here,
- A={a,b,p}
- C={p,q,r,s}
Therefore,
(AUC) = {a,b,p} U {p,q,r,s}
=> (AUC) = {a, b, p, q, r, s}
Again,
- B = {2,3}
Therefore,
(AUC) × B = {a, b, p, q, r, s} × {2,3}
=>(AUC) × B = {(a, 2), (a, 3), (b, 2), (b, 3), (p, 2), (p, 3), (q, 2), (q, 3), (r, 2), (r, 3), (s, 2), (s, 3)}
=> n[(AUC) x B] = 12
● Hence, n[(AUC) x B] = 12
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