Question

A) a ball of mass 0.20kg is thrown vertically upwards with an initial velocity of 20m/s. Calculate the maximum potential energy it gains as it goes up.

Answer 1

Answer:

Explanation:

will have the maximum potential energy at H max

then H max \frac{u^2}{2g}

= \frac{20^2}{2×10}

= \frac{400}{20}

= 20m

now as PE = mass × g × height

=> 0.2 × 10 × 20

=> 40 Joles