a(a+bc) for a= -1 b= 2 c=3
plese don't give me false answer.
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Step-by-step explanation:
a + b + C = 3 , a2 + b2 + c2 = 101
( a + b + c ) 2 = a + b2 + c2 + 2ab + 2bc + 2ca
9 = 101 + 2 ( ab + bc + ca )
( ab + bc + ca ) = - 46
a3 + b3 + c3 - 3abc (a+b+c)(a2 + b2 + c2- ab - bc - ac)
= (3)(101 + 46)
= 441
So, √a3 +b3 +c3 – 3abc = √441 = 21
two ans is there which ans u feel easy u write that first one is in the photo
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