Question

a) A Beam of light entering to a medium having refractive
index 1.63 from the medium with refractive index 133, what
Changes Would take place in the velocity of the light? How would light bend in this situation​

Answer 1

Explanation:

it is not verified

I made also the same question

Answer 2

Given:

n1 = 1.63

n2 = 1.33

To find:

1) v =?

2) θ =?

Explanation:

1)

The refractive index in terms of velocity of light is given by

   n = $\frac{c}{v}$  

⇒ $\displaystyle v =\frac{c}{n}$

Now the velocity of light having n1 = 1.63 is

v = $\frac{3\times 10^8}{1.63}$

v = 1.84 × $\mathbf{10^8}$ m\s

The velocity of light having n2 = 1.33 is

v = $\frac{3\times 10^8}{1.33}$

v = 2.25 × $\mathbf{10^8}$ m\s

Hence the velocity of light is increased when it travels from one medium to another.

2)

The bending angle of light when it travels from one medium to another is given by

tanθ = $\displaystyle\frac{n_1}{n_2}$

        = $\displaystyle\frac{1.63}{1.33}$

tanθ = 1.2255

θ = 50.78°

So the light will be bent at an angle of 50.78°.