a)A body projected vertically up from top of building of height H. find time after which it
hits the ground. b) The position of a particle is given by x = 4 - 5t - t
2
, where x is in metre
and t is in second. Find its instantaneous velocity at 2s.
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Explanation:
x=4-5t-t²
v=dx/dt= 0-5-2t
at t= 2s -5-2(2)= -1m/s
answer is 1m/s downward (because of -ve sign)
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