Question

(a) A body starts from rest and gains a velocity of 6 m/s in 2s of time. Find the acceleration of the body and its average velocity for the given time.
(b) A force of 24 N produces an acceleration of 3m/s2 on a body of mass m1 and an acceleration of
2m/s2 on a body of mass m2. What acceleration does it produce when applied on a combination of
the two bodies?​

Answer 1

Explanation:

a)

u=0

v=6m/s

t=2s

$a = \frac{v - u}{t}$

$a = \frac{6 - 0}{2}$

$a = 3 {ms}^{ - 2}$

avg. velocity = displacement/time

= 6/2

• =3m/s

b)

F=24N

on the 1st body

a=3m/s^2

then ,

F = ma

m = F/ a

=24/3

=8

on the 2nd body

a=2m/s^2

then,

m=24/2

=12

on combining, (12 + 8= 20)

24= 20×a

a=1.2 m/s^2

hope this might help you!!

Answer 2

Answer:

A.

a=v-u/t=6-0/2=3 m/s^2

F=m×s

F1=m1×3

F2=m2×2

If m1=8 kg

m2=12 kg

F=m × a

24=20×a

a=24/20=1.2 m/s^2

Sorry for late answer due to connection

If you like my answer Please mark me as brainliest. . . .