Question

A a can do a piece of work in 60 days. He worked for 15 days and then be done finish the remaining work in 30 days.The two together can finish the work in how many days?

Answer 1

AnswEr:

In 24 Days

Step by Step Explanation:-

$\bold{\underline{\sf{\pink{\;\;Given:-\;\;}}}}$

A can do work in 60 days and worked for 15 days.

B finish Remaining work in 30 days.

Let us Consider that Total Work = 1.

If A finishes Work in 60 days = $\sf\dfrac{1}{60}$

A worked for 15 days = $\sf\dfrac{15}{60} = \dfrac{1}{4}$

Now, Remaining Work = $\sf \; 1 - \dfrac{1}{4}$

$:\implies\sf\dfrac{3}{4}$

And, B finishes his work in 30 days.

$:\implies\sf\; 30 \times\dfrac{4}{3}$

$:\implies\large\boxed{\sf{\red{40 \; Days}}}$

$\rule{150}3$

$\bold{\underline{\sf{\pink{\;\;A + B \; Together\;\;}}}}$

$:\implies\sf\; \dfrac{1}{60} + \dfrac{1}{40}$

$:\implies\sf\; \dfrac{5}{120}$

$:\implies\sf\;\dfrac{1}{24}$

$\bold{\underline{\sf{\pink{They\; together\; can\; finish\; the \;work\; in \; 24\; Days}}}}$

Answer 2

$\huge\bold\green{Question}$

A a can do a piece of work in 60 days. He worked for 15 days and then be done finish the remaining work in 30 days.The two together can finish the work in how many days?

$\huge\bold\green{Answer}$

“A” can do work in 60 days and worked for 15 days.

Remaining work is finished by “ B” in 30 days

Let us assumed Total Work done = 1

If “A” finishes Work in 60 days = $\tt{\dfrac{1}{60}}$

“A” worked for 15 days = $\tt{\cancel\dfrac{15}{60} = \dfrac{1}{4}}$

Now, Remaining Work =$\tt { 1 - \dfrac{1}{4}}$

Remaining work =$\tt{\dfrac{3}{4}}$

Hence, “B” finishes his work in 30 days.

= $\tt{30 \times\dfrac{4}{3}}$

Total days = 40 days

So , according to the question

A + B works together =

= $\tt{ \dfrac{1}{60} + \dfrac{1}{40}}$

= $\tt{\cancel \dfrac{5}{120}}$

= $\tt{\dfrac{1}{24}}$

Hence they taken 24 days if both A and B works together