Question

A- A car makes 5oooo revolution to
travel a distence of 121km. The
diameter of the wheel of the
car is.​

Answer 1

Let the no. of revolution be 'n'

Let the circumference of wheel be (2×22/7×r) cm

A/q

n × circumference of wheel = 121 km

=> 50000 × 2 × 22/7 × r = 12100000 cm

=> r = 12100000 × 7 / 50000 × 2 × 22

=> r = 38.5

hence diameter= 2r

= 2 × 38.5

= 77 cm

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