Question

(a). A chord of length 12 cm is at distance of 8 cm from the centre of the circle
Determine length of the chord of the same circle which is at 6 cm from the
circle​

Answer 1

Answer:

the length of the chord is 16 cm

Answer 2

Given:-

A chord of length 12 cm is at distance of 8 cm from the centre of the circle.

To find :-

Length of the chord of the same circle which is at 6 cm from the

circle.

Solution:-

​

→Assume that centre of the circle be O and E The mid point of AB. AEO and BEO are both right angled triangle.

→i.e AE=   12/ 2  and EO=8cm, so R the radius of the circle is,

$=> \sqrt{6^{2}+8^{2} } = \sqrt{100}$

=> 10 cm.

→Now the chord CD is 6cm from O. Let F be the mid point of CD. CFO and DFO are both right angled triangle.

→FO = 6 ; CO = DO = 10cm

∴CF = DF

$=> \sqrt{10^2 -6^2} =\sqrt{100 -36} \\\\=> \sqrt{64} = \underline{8 cm.}$

so,

=> D = 2 * 8 = 16 cm.

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