Question

A. A circle touches all the four sides of a quadrilateral ABCD. Then AB + CD is equal to
(a) AD-BC
(b) BC-AD
(c) AD + BC
(d) (AD +BC)^2​

Answer 1

Answer:

AB+CD=AD+BC

if circle touches all the sides of quadrilateral then quadrilateral is square.

AB+CD=AD+BC

OPTION C