A. A circle touches all the four sides of a quadrilateral ABCD. Then AB + CD is equal to
(a) AD-BC
(b) BC-AD
(c) AD + BC
(d) (AD +BC)^2
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Answer:
AB+CD=AD+BC
if circle touches all the sides of quadrilateral then quadrilateral is square.
AB+CD=AD+BC
OPTION C
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