Question

(a) A cricket ball of mass 100g moving at a speed of 30m/sec is
brought to rest by a player in 0.03 sec. Find the average force
applied by the player​

Answer 1

Answer:

I guess the question is the rate of change in momentum

Mass=0.1kg

Initial Momentum=m×speed (u)=0.1×30=3

Final Momentum= m×rest (v)=0.1×0=0

Change in Momentum= Final-Initial =0−3=−3

Rate of change in momentum=(change in momentum)÷time taken

=(−3)÷0.03

=−100

Answer 2

Explanation:

This is the answer of :- 130+0.03 = 130.03