a
A cricket bat of mass 150 g khas an initial velocity
ū(3ỉ + 4ſ)m s^- 1
and
final velocity
ů = -(3 + 4ſ)m s-1
after being hit. The change in
momentum is
1. O
Zero
2. O-(0.45 î + 0.6 )kg m s-1
-(0.9 î + 1.2 ;)kg m s-1
3.
-5(i + i)kg m s-1
4.
Answers
Answered by
1
Answer:
Here, m=150g=0.15kg
u
=(3
i
^
+4
j
^
)ms
−1
v
=−(3
i
^
+4
j
^
)ms
−1
Initial momentum,
p
i
=m
u
p
i
=(0.15kg)(3
i
^
+4
j
^
)ms
−1
=(0.45
i
^
+0.6
j
^
)kgms
−1
Final momentum,
p
i
=m
u
p
f
=(0.15kg)(−3
i
^
−4j)ms
−1
=(−0.45
i
^
−0.6
j
^
)kgms
−1
Change in momentum, △
p
=
p
f
−
p
i
=(−0.45
i
^
−0.6
j
^
)kgms
−1
−(0.45
i
^
+0.6
j
^
)kgms
−1
=(−0.9
i
^
−1.2
j
^
)kgms
−1
=−(0.9
i
^
+1.2
j
^
)kgms
−1
Answered by
0
Answer:
105g...............................................
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