(a) A current of 1A flows in a series circuit containing an electric lamp and a conductor of 5Ω when connected to
a 10V battery. Calculate the resistance of the electric lamp.
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I= 1A
V= 10V
R1= 5Ω
R2=?
R1 and R2 are connected in series.
Therefore the effective resistance
Req= R1+R2
Req= 5+R2
We know that
V=IR
R= V/I
R2+5= 10
R2= 5Ω
Therefore the resistance of electric lamp is 5Ω
V= 10V
R1= 5Ω
R2=?
R1 and R2 are connected in series.
Therefore the effective resistance
Req= R1+R2
Req= 5+R2
We know that
V=IR
R= V/I
R2+5= 10
R2= 5Ω
Therefore the resistance of electric lamp is 5Ω
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