Physics, asked by effiongemma4986, 9 days ago

A a cylinder contain hydrogen gas at a pressure of 249 ke Pascal and temperature 27 degree Celsius ,. Its density is equal to 8.3 Mol - -1 K -1

Answers

Answered by kollojumadhavi
0

Answer:

-2-5 answer remove 3 in that

Answered by anjumanyasmin
0

Given : pressure = 249,temperature 27,density = 8.3.

We know that,

\begin{array}{l}P V=n R T \\P V=\frac{m}{M} R T \\P M=\left(\frac{m}{V}\right) R T\end{array}

\begin{aligned}\rho &=\frac{P M}{R T} \\&=\frac{249 \times 10^{6} \times 2 \times 10^{-\not 6}}{83 \times 300}\end{aligned}

  = =\frac{249 \times 2}{2490}=0.2 \frac{\mathrm{kg}}{\mathrm{m}^{3}}

So the the value of \rho is 0.2 \frac{\mathrm{kg}}{\mathrm{m}^{3}}.

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