a A {ectangle has peεi metee 132cm. its
length is acm more than twice its
width. Find its area?
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Answer:
SUPPOSE Width =x
then length = 2x +1
perimeter of rectangle = 2*(length +height)
132=2(x+2x+1)
132/2=(3x+1)
66= 3x+1
66-1=3x +1
65=3x
x=65/3=21.66
so length = 2x+1 = 2*21.66+1=44.33 cm. or 44 1/3
and width = x= 21.66 cm ans. or 21 2/3
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