a. A father is 7 times as old as his son. Two years ago the father was 13 times as old as his
son. What are their present ages?
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Answer:
Step-by-step explanation: let the sons age be 'x' and fathers age be' y'
so,
y=7x
⇒y-7x=0 ----eq 1
2 years ago,
y-2=13(x-2) .....eq2
y=7x
⇒ elimination method we get,
7x-2= 13x-26
26-2 = 13x-7x
4x=24
x=4
y=28
Step-by-step explanation:
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