Question

a. A father is 7 times as old as his son. Two years ago the father was 13 times as old as his
son. What are their present ages?
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Answer 1

Answer:

Step-by-step explanation: let the sons age be 'x' and fathers age be' y'

so,

y=7x

⇒y-7x=0 ----eq 1

2 years ago,

y-2=13(x-2) .....eq2

y=7x

⇒ elimination method we get,

7x-2= 13x-26

26-2 = 13x-7x

4x=24

x=4

y=28

Step-by-step explanation: