Question

a) A field is 600m long and 50m broad. A tank 30m long. 20m broad and 12m deep is
dug in the field. The earth taken out of it is spread evenly over the field. Find the height
of the field raised by it.

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Answer 1

Answer:

volume of tank= 30x20x12

=7200

areas of field x h=7200

600 x 300 x h=7200

180000h=7200

h = 7200/180000

Step-by-step explanation:

$Hope \: it \: helps...!!$

Answer 2

Answer:-

★ Given:

• Dimension of field = 600m long by 50m

• Dimension of earth taken out = 30m long by 20m board by 12m deep

★ To Find:

• Height of field raised when earrh taken out spread through field.

★ Solution:

➣ Finding volume of earth taken out:

Volume of earth taken out

= length × breadth × Height

= 30 × 20 × 12

= 600 × 12

= 7200 m³

➣ Finding area of earth taken out

Area of tank

= length × breadth

= 30 × 20

= 600m²

➣ Finding area of field

Area of field

= length × breadth

= 600 × 50

= 30000m²

➣ Finding area of remaining field

Area of remaining field

= Area of field - area of earth taken out

= 30000 - 600

= 29400m²

➣ Finding Height raised when earth taken out spread through:

Height

= Volume ÷ Area

= 7200m³ ÷ 29400m²

= 0.24489.. m

∴ Height of the feild raised by 0.25m(approx.)

★ Formula to be remembered:-

▪︎Volume of cuboid = length × breadth × height

▪︎Volume of cube = Side × Side × Side

▪︎Volume of cuboid = π × radius² × height

▪︎Volume of cone = ⅓× height × π × radius²