A×A has 9 elements among them are (-2,0) and (0,3) a.then find A b.Write A×A
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n(A×A)=9
Set A={−1,0,1} Since (−1,0) and (0,1) are elements in A×A
Remaining elements
={(−1,−1),(−1,1),(0,−1),(0,0),(1,−1),(1,0),(1,1)}
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