Math, asked by bealoverofpeace, 9 months ago

a) A hunter is standing 350 feet away and fired a bullet straight up at a bird on a tree at a rate of 15 ft/sec. At what rate is the distance between the hunter and the bullet increasing [11 marks] i) 20 seconds after liftoff? ii) 1 minute after liftoff?

Answers

Answered by krishgoel679
0

Answer:

I 15*20 =300

in 20 secs distance change is 50ft

in I sec 50/20 = 2.5ft\sec

ii 60*20=1200

in 60 secs dist change is 850ft

in 1 sec 850/60=14.16

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