Math, asked by chimanramchaudhari9, 9 months ago

`A`a is twice as old as B's. five years ago A's age was three times B's age. find their present ages.

Answers

Answered by meghanabhuvana2020
4

Let the ade of A be a and B be b.

a = 2b……….(1)

Five years ago

A’s age was a-5 and B’s age was b-5

a-5 = 3(b-5)

a-5 = 3b -15………(2)

We have to solve two linear equations (1) & (2)

Substituting value of a =2b in (2)

2b -5 = 3b - 15

b = 10 & a = 20

So ages of A & B are 20 & 10 years respectively.

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Answered by laxmipriyam876
1

Answer:

it 15 years beac use one type of process is 5 × 3 = 15 the A age is 15 years

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