`A`a is twice as old as B's. five years ago A's age was three times B's age. find their present ages.
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Let the ade of A be a and B be b.
a = 2b……….(1)
Five years ago
A’s age was a-5 and B’s age was b-5
a-5 = 3(b-5)
a-5 = 3b -15………(2)
We have to solve two linear equations (1) & (2)
Substituting value of a =2b in (2)
2b -5 = 3b - 15
b = 10 & a = 20
So ages of A & B are 20 & 10 years respectively.
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Answered by
1
Answer:
it 15 years beac use one type of process is 5 × 3 = 15 the A age is 15 years
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