(a) A KCl solution is prepared by mixing 8g of NaCl (MW=74g/mol) with 250mL of H2O. Calculate the molarity; (b) A KCl solution is prepared by mixing 5g of KCl with 200g of H2O. Calculate the percent (m/m) of the solution.
Answers
KCI solution is prepared by mixing 8g of Nacl mw ecttt
(a) A NaCl solution is prepared by mixing 8g of NaCl (MW = 58.5 g/mol) with 250mL of H2O. Calculate the molarity.
solution : no of moles of NaCl = mass of NaCl/molar mass of NaCl
= 8/58.5 = 0.137 mol
molarity of NaCl solution = no of moles of NaCl/volume of solution in L
= 0.137 mol/(250/1000 L)
= 0.548 M
molarity of the solution is 0.548 M.
(b) A KCl solution is prepared by mixing 5g of KCl with 200g of H2O. Calculate the percent (m/M) of the solution.
solution : mass of KCl = 5 g
mass of H2O = 200 g
mass of solution = mass of KCl + mass of H2O
= 5g + 200g = 205 g
so, percentage of (w/W) of the solution = mass of solute( KCl)/mass of solution × 100
= 5/205 × 100
= 500/205
= 2.44 %
Therefore percentage (w/W) of the solution is 2.44 %.
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