Question

(a) A man deposited some amount of money
in the bank for each of his daughter in
such a way that when each of his
daughter's age is 18 years, each of them
will get 1,20,000. The rate of simple
interest of the bank is 10% and the
present age of the daughters are 13
years and 8 years. How much money
he deposited in the bank for each
daughter?​

Answer 1

Answer:

18000 rupees

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

for elder daughter,

time of investment = 18-13 = 5 years

rate of interest = 10%

let deposited amount be X rupees

=> X×10×5/100 +X = 120000

=> X/2+X = 1200000

=> X = 120000×2/3 = 80,000 rupees

for younger daughter,

time of investment = 18-8 =10 years

rate of interest = 10%

let deposited amount be Y rupees

=> Y×10×10/100 + Y = 120000

=> 2Y = 120000

=> Y = 60000 rupees .

therefore,

deposited money each

(1) 60,000 rupees

(2) 80,000 rupees

Total deposited amount = 140,000 rupees

Formula used:-(1) SI = P×r×t /100

(2) maturity amount = SI + P

hope this helps you