Math, asked by anujkumar8400556068, 1 month ago

a) a man runs a total distance in three parts in the ratio 4:3:1 with the constant speeds of 12m/sec, 9m/sec, and 10m/sec. What is the average speed of the man for the complete journey? ​

Answers

Answered by Mholya
0

Answer:

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Answer

Let total distance be x

First Part

Distance, d

1

=

3

2x

Time, t

1

=

v

1

d

1

=

3×30

2x

=

90

2x

Second Part

Distance, d

2

=

3

x

Time, t

2

=

v

2

d

2

=

3×40

x

=

120

x

Average Speed

v

av

=

Totaltime

Totaldistance

=

90

2x

+

120

x

x

=

45

1

+

120

1

1

=

360

8

+

360

3

1

=

11

360

=32.7km/h

Answered by aswanthabhianndh
0

Answer:

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