Math, asked by rajkrishna2920, 6 months ago

A) A man spends 3/8 of his money and still has 720 left with him. How much
money did he have at first?​

Answers

Answered by mauyakhbhattacharjee
1

Answer:

let the man has ₹8

So, Money spent = 3/8×8= ₹3

So Money left = 8-3= 5

Atq

money left = 720

so, when 5.......money left 720

when 1.......720/5= 144

when 8...... 144×8 = ₹1152.

So he had ₹1152.

Similar questions