Question

(a) A metallic wire has a resistance R . It is cut into 2 equal parts and the 2 equal parts are connected in parallel. Find the equivalent resistance of the combination. (b) A current of 0.5A flows through an electric charge that flows through the circuit . ​

Answer 1

Answer:

(a) A metallic wire has a resistance R .

It is cut into 2 equal parts

Each of resistance = R/2

The 2 equal parts are connected in parallel.

The equivalent resistance of the combination -

$equivalent \: resistane \: {r}^{.} = \frac{ \frac{r}{2}. \frac{r}{2}}{ \frac{r}{2} + \frac{r}{2} }$

R' = R/4

$= \frac{ {r}^{2} \div 4}{ r } = \frac{r}{4}$

(b) A current of 0.5A flows through an electric charge that flows through the circuit .

Then,

V =I*R'

V = 0.5*R/4 = 0.125 R volts

Answer 2

Answer:

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