Question

a) A number is selected at random from the numbers 1 to 30.
What is the probability that -
1) it is divisible by 3 or 7
2) it is divisible by 5 or 13 ​

Answer 1

Answer:

Explanation:

Let A be event of selecting a number divisible by 3. B be the event of selecting a number divisible by 7.

Proability tutorial

A = { 3, 6, 9, 12, 15, 18, 21, 24, 27, 30 }, so n(A)=10

B = { 7, 14, 21, 28 }, n(B)= 4

Probability problems

Since A and B are not mutually exclusive So :

Probability addition rule

Probability problems

Subject: Probability - Quantitative Aptitude - Arithmetic Ability

answer is 1 / 30

hope you are satisfied

pls mark me brainlist

Answer 2

Answer:

Hello!!

Step-by-step explanation:

1)From 1 to 30 there are 30 numbers so numbers that are divisible by 3 are 10 and numbers divisible by 7 are 4 .so total are 7+4=11

Probability = 11/30

2)from 1 to 30 the numbers divisible by 5 are 6 & numbers divisible by 13 are 2. So total numbers are 6+2=8.

Probability = 8/30 = 4/15