Question

(a) A pair of adjacent angles of a parallelogram is such that one is 24° less than twice the other. Find the pair​

Answer 1

$\huge\frak{\color{red}{Answer:-}}$

102°; 78°.

$\large\bold\color{tan}{\underbrace{Explanation}:-}$

Sum of adjacent angles of a parallelogram is 180°. Let first angle be x then other angle is (x-24)°. Applying all the values :-

$x + (x - 24) = 180$

$= > x + x - 24 = 180$

$= > 2x - 24 = 180$

$= > 2x = 180 + 24$

$= > 2x = 204$

$= > x = \frac{204}{2} = 102$

Hence, first angle is x = 102°

other angle is (x-24) = 102-24 = 78°.

So, pair of angles are 102° and 78°