Question

A
A particle A, of mass 6 Kg , travelling in
a straight the at 5ms- collides with a
particle B, of mass 4kg, travelling in a
same straight line at the opposite direction
with a speed of 3ms-1. Given that after the
collision particle A continues to move in the same
direction at 1.5ms-1, what does
particle B move with after the collision?
​

Answer 1

Explanation:

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Answer 2

Answer:

2.25m/s

Explanation:

By momentum conservation,

M1U1+M2U2 = M1V1+M2V2

6*5 + 4(-3) = 6*1.5 + 4(V)

solving,

V=2.25m/s

Hope this helped you. ;p