Question

(a)
A person of mass 'm' is standing in a lif. Find his apparent weight when lift is (show mathematical
calculation)
A
moving upward with uniform acceleration 'a'.
(ii)
moveing downward with uniform acceleration a' (
a
g)
it
falls freely.​

Answer 1

Answer:

Hey I know.

Explanation:

1. mg+ma

2. mg-ma

3. When lift falls freely it's apperent weight is zero.

Because of its free fall.