Physics, asked by mrstrange13, 10 months ago

(a) A person of mass 'm' is standing in a lift. Find his apparent weight
when the lift is
(i) Moving upward with uniform acceleration 'a'.
(ii) Moving downward with uniform acceleration 'a' (< g).
(iii) falls freely.
(b) Explain why, it is easier to pull a lawn mover than to push it.​

Answers

Answered by kinsjackson
5

Answer:

a) i)When lift is moving up,

 R-mg=ma

     R=m(a+g)

ii)When lift is moving down,

   mg-R=ma

  R=m(g-a)

iii)When lift is falling freely, a=g

   R=m(g-g)

      =0  ie, the body is weightless.

b) Taking equation R=m(g-a) into account,

            The normal reaction(force) is greater when we pull a lawn.

Please mark it brainliest

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