Question

A
A person purchased 3 chaises
and 2 tables for 1200 Rs. And then
posed Rs 2400 for 6 chairs and
2 tables. Then what is the cost of one table and one chair​

Answer 1

=1200/2 =6/2400

600 =400

cost of one table =600rupees

cost of one chair=400rupees

Answer 2

$\underline{\boxed{\bold{ \bigstar \; Question \; \bigstar }}}$  

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➠ A person purchased 3 chairs  and 2 tables for 1200 Rs. And then  paid Rs 2400 for 6 chairs and  2 tables. Then what is the cost of one table and one chair​ ?

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$\underline{\boxed{\bold{ \bigstar \; Important \; Information \; \bigstar }}}$  

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❏ Usually, we solve this type of question by the concept of pair of linear equation in two variables.

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❏ We assume 2 variables for our answer and proceeding according to given conditions that leads to formation 2 equations. After solving these 2 equations we get our answer.  

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$\underline{\boxed{\bold{ \bigstar \; Given \; \bigstar }}}$

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➠ Cost of 3 chairs + 2 tables = Rs.1200

➠ Cost of 6 chairs + 2 table = Rs.2400

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$\underline{\boxed{\bold{ \bigstar \; Answer \; \bigstar }}}$  

Let's Start !

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Let us assume as follow :

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           ❖ Let cost of one chair = x

           ❖ Let cost of one table = y

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According to given condition,

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$\star \; \; \; \; \; \; \; \; \boxed { \orange { :\longmapsto \; 3x + 2y = 1200 } } \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \{Equation \; : 1\}$

$\star \; \; \; \; \; \; \; \; \boxed { \orange { :\longmapsto \; 6x + 2y = 2400 } } \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \{Equation \; : 2\}$

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Now let's solve these equations to get our answer !

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$\orange { :\longmapsto \; 6x + 2y = 2400 }$

$:\implies 2y = 2400 -6x \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \{Equation \; : 3\}$

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Now let's substitute this values in Equation : 1

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$\orange { :\implies \; 3x + 2y = 1200 }$

$:\implies \; 3x + 2400 - 6x = 1200$

$:\implies \; 3x = 1200$

$:\implies \; x = \dfrac{1200}{3}$

$\underline {\boxed { \red{ :\implies \; x = 400 } } }$

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Now let's substitute vale of "x" in Equation : 3

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$\orange { :\implies 2y = 2400 -6x }$

$:\implies 2y = 2400 -(6 \times 400)$

$:\implies 2y = 2400 -2400$

$:\implies 2y = 0$

$\underline { \boxed { \red{:\implies y = 0} } }$

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NOTE :

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• Here there is mistake in question. But method which I gave in answer is correct. Re-check your question and solve as I have proceed. If then also you have doubt feel free to comment.

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• Cost of one table can't be zero rupees so please re-check your question.

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$\boxed{\boxed{\bold{\therefore Cost \; of \; 1 \; chair = Rs.400}}}$

$\boxed{\boxed{\bold{\therefore Cost \; of \; 1 \; table = Rs.0} }}$

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Hope this helps u.../

【Brainly Advisor】