Question

A
A projectile is throws 400m above the
ground at the instant of 4s at intial
velocity 10m/s avoiding
air resistance find
1)Vy= ? 2) Vr= ?
3)α= ?
4)R=?
5) T = ?


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Answer 1

Answer:

GIVEN THAT

HEIGHT(S)=400m

TIME=4SECOND

INITIAL VELOCITY (U)=10M/S

FINAL VELOCITY (V)=0M/S

USING FORMULA,

v=u+at

0m/s=10m/s+a×4sec

-10m/s=a×4sec

-10m/s÷4sec=a

-2.5m/s=a

Now,You have acceleration=-2.5m/s

height=400m

time=4second