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Question No. 11
Per a *** and ife. Then there is a polynomial p() for
|f(x)-p(x)se for a sxst
|(x)-P(x)ze for a suso
|f(x)] ++[p(x)/ºse for a sxsb
|f(x)*+/p(x)/?se for a sxsb
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please right aproper questionno one can understand this