A
A sample of pure water, whatever the
source always cat ontains by
Mass of oxygen and 11.1% by Mass of
hydrogen.
:-)
Answers
Answered by
1
Answer
A sample of pure water,whatever the source always contains 88.8% by mass of oxygen & 11.1%by mass of hydrogen.
The total amount of percentage is 100, therefore they are divided in a constant ratio.
H2O contains H and O in a fixed ratio by mass. It illustrates the law of constant composition or in other words law of conservation of energy. So, they are divided in a ratio of 1:8 therefore mass of Oxygen is 88.8%.
Hope it helps
Make me the brainliest
A sample of pure water,whatever the source always contains 88.8% by mass of oxygen & 11.1%by mass of hydrogen.
The total amount of percentage is 100, therefore they are divided in a constant ratio.
H2O contains H and O in a fixed ratio by mass. It illustrates the law of constant composition or in other words law of conservation of energy. So, they are divided in a ratio of 1:8 therefore mass of Oxygen is 88.8%.
Hope it helps
Make me the brainliest
Answered by
0
Answer:
H is 11.1% by wt &
O is 88.9% by wt
which makes it to
simplest ratio of 1:8
this is acc to law of definite proportions (proposed by Proust)
Explanation:
ALTERNATIVE NAMES: law of definite proportion, sometimes called Proust's law, or law of constant composition
THE LAW STATES THAT: " a given chemical compound always contain its component elements in fixed ratio and does not depend on its source and method of preparation."
hope that it helps you :)
if u like mark it as Brainliest!!!
Similar questions