A a square oabc is encrypted in a quadrant opbq u of a circle as shown in the figure is O A is equals to 21 find the area of the shaded region
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given OA=AB=BC=CO=21cm
In right △OAB,OB2=OA2+AB2
⇒OB=212+212=212cm=radius
∴ area of shaded region = area of quad. OPBQ - area of square
= 41×πr2−(21×21)
= 41×722×(212)2−441
∴area of shaded region=252 cm2
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