(a) A student has mixed the solutions of lead (II) nitrate and potassium iodide. i. What was the color of the precipitate formed? Can you name the compound precipitated? ii. Write the balanced chemical equation for this reaction. iii. What type of reaction is it?
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When a solution of potassium iodide is added to lead nitrate solution, then a precipitate is formed. This precipitate is of lead iodide which is yellow in colour. Thus
(a) A precipitate of lead iodide is observed. The colour of the precipitate formed is yellow.
(b) A balanced chemical equation for the reaction is shown as follows
2KI (aq) + Pb(NO3)2 (aq) → PbI2 (s) + 2KNO3 (aq)
(c) the reaction is an example of double displacement reaction.
@skb
(a) A precipitate of lead iodide is observed. The colour of the precipitate formed is yellow.
(b) A balanced chemical equation for the reaction is shown as follows
2KI (aq) + Pb(NO3)2 (aq) → PbI2 (s) + 2KNO3 (aq)
(c) the reaction is an example of double displacement reaction.
@skb
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Answer:
dude, thats what even i am asking
Explanation:
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