Question

a(a
$a( {a}^{2} + a + 1) + 5$
+a+1)+5​

Answer 1

Answer:

wiil be working

have been working

will have been working

had worked

Answer 2

Step-by-step explanation:

5

x+1

+5

2−x

=5

3

+1

{5}^{x + 1} + {5}^{2 - x} = 1265

x+1

+5

2−x

=126

{5}^{x} .5 + {5}^{2} . {5}^{ - x } =1265

x

.5+5

2

.5

−x

=126

{5}^{x} .5 + \frac{25}{ {5}^{x} } = 1265

x

.5+

5

x

25

=126

5y + \frac{25}{y} = 126 \: \: \: \: where \: {5}^{x} = y5y+

y

25

=126where5

x

=y

5 {y}^{2} + 25 = 126y5y

2

+25=126y

5 {y}^{2} - 126y + 25 = 05y

2

−126y+25=0

5 {y}^{2} - 125y - y + 25 = 05y

2

−125y−y+25=0

5y(y - 25) - 1(y - 25) = 05y(y−25)−1(y−25)=0

(y - 25)(5y - 1) = 0(y−25)(5y−1)=0

y - 25 = 0 \: \: \: or \: \: \: 5y - 1 = 0y−25=0or5y−1=0

y = 25 \: \: \: \: or \: \: \: \: y = \frac{1}{5}y=25ory=

5

1

{5}^{x} = 25 = {5}^{2} \: \: \: \: \: or \: \: \: \: \: {5}^{x} = {5}^{ - 1}5

x

=25=5

2

or5

x

=5

−1

x = 2 \: \: \: \: \: or \: \: \: \: \: x = - 1x=2orx=−1

Hence, 2 and -1 are the roots of the given equation....

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Hope this will help you...✨✨✨