Question

A
a. The area of four walls of a room is 44 m². The length and breadth are 6 m and
5 m respectively. Find the total surface area of the room.

Answer 1

Given :-

• The area of 4 walls of room = 44m².
• Length of room = 6m.
• Breadth of room = 5m.

To Find :-

• Total surface Area of Room = ?

Solution :-

we know That, Area of Four Walls of Room is 2(l+b)*h.

Putting values we get :-

→ 2(6+5)*h = 44

→ 2*11 * h = 44

→ 22*h = 44

→ h = 2m.

_____________________

So,

→ TSA of Room = 2(lb + bh + hl)

→ TSA = 2(6*5 + 5*2 + 6*2)

→ TSA = 2(30 + 10 + 12)

→ TSA = 2 * 52

→ TSA = 104m².

Hence, Total Surface Area of room is 104m².

Answer 2

Step-by-step explanation:

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Area=2(l+b)×h

44=2(6+5)×h

44=2(11)×h

44=22×h

h=44/22

h=2 m

T.S.A= 2(lb+bh+hl)

T.S.A= 2(6×5+5×2+2×6)

T.S.A= 2(30+10+12)

T.S.A= 2(52)

T.S.A= 104 m²

Thank you

@ Twilight Astro ✌️☺️♥️