Question

A A train covers 360km in 649? What
is the
the train 2
speed of​

Answer 1

Answer:

Since v= s /t

Hence v= 360/t -(1)

The speed is increased by 5 ,so the speed will be (v+5)km/hrs and the time will be (t-1)hrs

Hence (v+5)=360/(t-1) -(2)

Put the value of v from eq 1 in eq 2

(360/t)+5 =360/(t-1)

Take LCM

(360+5t)/t =360/(t-1)

Cross multiply

(360+5t)(t-1) =360t

360t- 360+5t^2-5t=360t

Hence 5t^2-5t-360=0

5t^2-(45-40)t-360=0

5t^2-45t+40t-360=0

(5t+40)(t-9)=0

Hence t= 9, -8

Time will be 9 hrs

Hence v=360/9

v=40 km/hrs

Answer 2

Answer:

Equation 1 will be 360/v=t

Equation 2 will be 360/(v+5)=t-1

Solve these two equations to get the answer

Step-by-step explanation:

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