Question

A a train starting from rest attain of 72 kmh_1 assuming that the acceleration is uniform find the acceleration and the distance traveled by the train for attaining this velocity
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Answer 1

First, This question is incomplete

Please mention time =5 minutes

5 mins = 300 sec

72km/h=20m/s

Acceleration=initial position-final position/total time taken

a=20-0/300

acceleration=1/15m/s

Distance covered in that time=

s=ut+1/2at2

s=0X20+1X1X300^2

s=3000 Meter

or

3 km