Question

A) a triangle has an area 49.5 . if the base of the triangle is 9cm, what is the height of the triangle?

Answer 1

Answer :-

11cm

Explanation :-

Given :

Area of the triangle = 49.5cm^2

Base of the triangle = 9cm

To Find :

Height of the triangle = ?

Solution :

We know,

Area of the triangle is equal to:

$\boxed{\sf{}\dfrac{1}{2}\times b\times h}$

where,

h is the height and,

b is the breadth,

Put their values and find “h”

$:\implies \sf{} 49cm^2=\dfrac{1}{2}\times 9cm\times h$

$:\implies \sf{} 49cm^2=\dfrac{9cm}{2}\times h$

$:\implies \sf{} 49cm^2\div \dfrac{9cm}{2}= h$

$:\implies \sf{} 49cm^2\times \dfrac{2cm}{9}= h$

$\sf{}\therefore h=11cm$

Therefore,height of the triangle is 11cm (approx)