Science, asked by devisharda6346, 2 months ago

A
A trolly while going
down a
inaind placé hal an accieraliong
2 cm/s. What will be its velocity
of 5s after start​

Answers

Answered by akashray96
1

Answer:

mark me as brainliest

Explanation:

10 cm/ sec

Answered by Anonymous
3

Answer:

Hmm

here is ur answer with exp,lan,ation

hope it is helpful

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Explanation:

Answer:

Answer:Explanation:

Answer:Explanation:Given :-

Answer:Explanation:Given :-Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²

Answer:Explanation:Given :-Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²Initial speed of trolley, u = 0 (As trolley starts from rest)

Answer:Explanation:Given :-Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²Initial speed of trolley, u = 0 (As trolley starts from rest)Time taken by trolley, t = 3 seconds

Answer:Explanation:Given :-Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²Initial speed of trolley, u = 0 (As trolley starts from rest)Time taken by trolley, t = 3 secondsTo Find :-

Answer:Explanation:Given :-Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²Initial speed of trolley, u = 0 (As trolley starts from rest)Time taken by trolley, t = 3 secondsTo Find :-Final speed, v = ??

Answer:Explanation:Given :-Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²Initial speed of trolley, u = 0 (As trolley starts from rest)Time taken by trolley, t = 3 secondsTo Find :-Final speed, v = ??Formula to be used :-

Answer:Explanation:Given :-Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²Initial speed of trolley, u = 0 (As trolley starts from rest)Time taken by trolley, t = 3 secondsTo Find :-Final speed, v = ??Formula to be used :-1st equation of motion,

Answer:Explanation:Given :-Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²Initial speed of trolley, u = 0 (As trolley starts from rest)Time taken by trolley, t = 3 secondsTo Find :-Final speed, v = ??Formula to be used :-1st equation of motion, i.e, v = u + at

Answer:Explanation:Given :-Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²Initial speed of trolley, u = 0 (As trolley starts from rest)Time taken by trolley, t = 3 secondsTo Find :-Final speed, v = ??Formula to be used :-1st equation of motion, i.e, v = u + atSolution :-

Answer:Explanation:Given :-Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²Initial speed of trolley, u = 0 (As trolley starts from rest)Time taken by trolley, t = 3 secondsTo Find :-Final speed, v = ??Formula to be used :-1st equation of motion, i.e, v = u + atSolution :-Putting all the values, we get

Answer:Explanation:Given :-Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²Initial speed of trolley, u = 0 (As trolley starts from rest)Time taken by trolley, t = 3 secondsTo Find :-Final speed, v = ??Formula to be used :-1st equation of motion, i.e, v = u + atSolution :-Putting all the values, we getv = u + at

Answer:Explanation:Given :-Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²Initial speed of trolley, u = 0 (As trolley starts from rest)Time taken by trolley, t = 3 secondsTo Find :-Final speed, v = ??Formula to be used :-1st equation of motion, i.e, v = u + atSolution :-Putting all the values, we getv = u + at⇒ v = 0 + 0.02 × 3

Answer:Explanation:Given :-Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²Initial speed of trolley, u = 0 (As trolley starts from rest)Time taken by trolley, t = 3 secondsTo Find :-Final speed, v = ??Formula to be used :-1st equation of motion, i.e, v = u + atSolution :-Putting all the values, we getv = u + at⇒ v = 0 + 0.02 × 3⇒ v = 0.02 × 3

Answer:Explanation:Given :-Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²Initial speed of trolley, u = 0 (As trolley starts from rest)Time taken by trolley, t = 3 secondsTo Find :-Final speed, v = ??Formula to be used :-1st equation of motion, i.e, v = u + atSolution :-Putting all the values, we getv = u + at⇒ v = 0 + 0.02 × 3⇒ v = 0.02 × 3⇒ v = 0.06 m/s

Answer:Explanation:Given :-Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²Initial speed of trolley, u = 0 (As trolley starts from rest)Time taken by trolley, t = 3 secondsTo Find :-Final speed, v = ??Formula to be used :-1st equation of motion, i.e, v = u + atSolution :-Putting all the values, we getv = u + at⇒ v = 0 + 0.02 × 3⇒ v = 0.02 × 3⇒ v = 0.06 m/sHence, the final velocity of trolley is 0.06 m/s.

Important Term :-

Important Term :-Final speed - Final speed is that speed which is acquired by the body after its start. It is denoted by v. When a body finally comes to rest, its final speed is zero.

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