Question

(a) a² - 2b² +3c²; when a=0,b=-1, C=1​

Answer 1

$\sf \: a \: = 0 \\ \sf b = - 1 \\ \sf c = 1$

$\sf {a}^{2} - {2b}^{2} + {3c}^{2} \\ \sf \: = {(0)}^{2} - 2 {( - 1)}^{2} + 3 {(1)}^{2} \\ \sf = 0 - 2 + 3 \\ \sf = 1$

Answer 2

Answer:

2+3 = 5

because the no. is only one

and a ki value zero so a value is also zero