a(A2+a+1)+5 and find its value for a=0,a=1,a=-1
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Let p(a) = a(a²+a+1)+5
i) If a = 0 then
value of p(0) = 0(0+0+1)+5
= 0+5
= 5
ii) If a = 1 then
p(1) = 1(1²+1+1)+5
= 1×3+5
= 3+5
= 8
iii) If a = -1 then
p(-1) = (-1)[(-1)²+(-1)+1]+5
= (-1)[1-1+1]+5
= (-1)×1 + 5
= -1 + 5
= 4
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