a(a²+b²)x²+b²x-a=0
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Answer:
a²b² x² + b²x - a² x - 1 = 0
b² x( a²x + 1 ) - ( a² x + 1 ) = 0
( a² x + 1 ) ( b² x - 1 ) = 0
Therefore ,
a²x + 1 = 0 or b²x - 1 = 0
x = ( - 1 / a² ) or x = 1 / b²
I hope this helps you.
:)
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