a) A6 cm object is placed perpendicular to the principal axis of a convex lens of focal
length 15 cm. The distance of the object from the lens is 10 cm. Find the position, size
and nature of the image formed, using the lens formula.
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Answer:
f = +15 cm
u = -10 cm
h = +6 cm
1/f = 1/v - 1/u
So, 1/v = 1/f + 1/u = 1/15 - 1/10
= -1/30
v = -30 cm => Image is formed on the same side as that of object.
h' = v/u * h = -30/-10 * 6
h' = +18 cm
So the image formed is virtual, erect and enlarged.
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